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Regular expression to replace text in quotes

Here’s my data:
value_1_col1 = « {« number »:100, « name »: »sample »} »

value_1_col2 = « {« number »:200, « name »: »sample2″} »

value_1_col3 = « {« number »:100, « name »: »sample »} »

value_1_col4 = « {« number »:200, « name »: »sample2″} »

I want to write a regular expression that uses string replacement, or substitution, that I can apply to the string and that will result in:
value_1_col1 = « 100, « sample » »

value_1_col2 = « 200, « sample2″ »

value_1_col3 = « 100, « sample » »

value_1_col4 = « 200, « sample2″ »

I know that the regexp substitution is « .* » would replace « name » with the result of calling str.lower() on « name », but I am unsure if it would replace all occurrences of « name » so that every « name » in the string would be lowercased.
Or is there an easier way to do this that does not require using regexp?

A:

Using re.sub() and lowercasing the result:
In [9

https://colab.research.google.com/drive/1AB1eKCKhvCh8-zyH1G_-uza6RPkP6OaU
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